03 calculation of theoretical data

Theoretical expectations:
    When the clock A is moving to the East, and the clock B is moving to the West, we can get nether relations:
    
   
    V - the speed of clock relative to the ground, U - the speed of the earth in universe, T0 - time of movement.
    The difference of time between both clocks:
    ¡­¡­¡­¡­¡­¡­¡­¡­¡­Equ. 3.1
   When the revolving bar rotate 180 degrees, here, the clock A is moving to the West, and the clock B is moving to the East, so:
    ¡­¡­¡­¡­¡­¡­¡­¡­¡­Equ. 3.2
    We subtract this record from previous:
    ¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­¡­Equ. 3.3
     Because the actual record is beat frequency, so the difference of time of twice beat frequencies is:
     ¡­¡­¡­¡­¡­¡­¡­Equ. 3.4
    - frequency of clocks, - frequency of the beat freqiency
     When the frequency of the conter is , the difference of twice conters is:
     ¡­¡­¡­¡­¡­Equ. 3.5
   the beat frequency is 53Hz, every beat frequency can get a data, so T0=.1/53 seconds.
   =80Mhz.
    The rotating speed of the principal axis is 6 revolution per second, the rotating radius of the clock is 0.45 meter, so the linear velocity of the clock is 17 m/s.
    If U=30Km/s (the earth moves towards the east ), then:
    53
    If U=250Km/s (the solar system moves towards the north), then:
    441

Actual data:
    Let's look at following actual data: (Decimal)
    Table 3-1

    The amount of address is 8, the column always is 8. But then, the line will sostenuto increase with the rotations of the revolving bar.
    Data Subtraction which moving in opposite directions we can get:
                  Table 3-2:

    It is must to point out: these data is gotten from onee measurement. In fact, the frequency of the OCXO exist phenomenon of slight dithering, besides, the circuit itself has noise. So it is natural that the single data is different. Because the revolution is not limited, we can get more data and average a set of amount of data to eliminate incidental factor or  interference.

zhan, LiKui 6/18/2007

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